Why eukaryotic cells wall off their chemistry into organelles, how the two energy-converting organelles (mitochondria and chloroplasts) descend from captured bacteria, and how the nucleus controls traffic across its envelope. Verified against Alberts, Molecular Biology of the Cell, 7th ed., Chapters 12 & 14.
Source: Ch. 12 (compartments) + Ch. 14 (mitochondria/chloroplasts)Format: Scantron MCQStudy mode: click any option for full reasoning
correct answer + mechanism distractor = named misconception▲ amber = lecture diverges from textbook
§Introduction
The defining structural fact of a eukaryotic cell is internal membranes. A bacterium runs all its chemistry in one open cytoplasm; a eukaryotic cell partitions incompatible reactions into membrane-enclosed organelles, each a distinct chemical environment with its own enzymes, pH, and ion composition. This buys specialization — but it also creates a hard logistics problem: proteins made in the cytosol must be delivered to the right compartment, which is the subject of Topic 5b.
Two organelles get special attention because they are, in a real sense, former bacteria. Mitochondria and chloroplasts arose by endosymbiosis — an ancestral cell engulfed a bacterium and, instead of digesting it, kept it. The evidence is written into their structure: their own circular genomes, their own bacterial-type ribosomes, their double (or triple) membranes, and their inability to form de novo. This is not a hypothesis presented for balance — it is the consensus explanation, and the exam expects you to marshal the evidence for it.
This guide follows the lecture's two deep dives — the mitochondrion (structure, oxidative phosphorylation, its genome and maternal inheritance) and the nucleus (envelope, pore complex, import/export) — and restores three pieces of Ch. 12/14 the lecture skimmed or got wrong: the correct three-membrane architecture of chloroplasts, the peroxisome, and the topological logic that unifies the endomembrane system. Where the lecture's dates or membrane counts diverge from the record, it's flagged in amber.
◎Learning Objectives
What the exam will hold you responsible for
Explain why compartmentalization is advantageous and identify the major organelles and their functions.
State the endosymbiotic theory and list the concrete evidence (own DNA, own ribosomes, double membrane, no de novo formation) — and place Margulis's original proposal correctly in time.
Describe mitochondrial architecture: outer vs inner membrane, cristae, matrix, intermembrane space, and the two chemical compartments this creates.
Trace oxidative phosphorylation: electron transport pumps H⁺ (matrix → intermembrane space), building the proton-motive force that drives ATP synthase (~3 ATP per turn).
Characterize the mitochondrial genome: circular and bacterial-like, with bacterial-type ribosomes (and the antibiotic-selectivity problem this creates), mostly nuclear-encoded proteins, and strictly maternal inheritance.
Give the correct chloroplast structure: three membrane systems — outer, inner, and thylakoid — not two.
Describe the nuclear envelope and pore complex: double membrane continuous with the ER, eightfold-symmetric NPCs, and NLS/NES-directed import/export.
Explain peroxisome function and the topological equivalence that links the lumens of the endomembrane system to the cell exterior.
1Why Compartments? Eukaryotic Organization
Bottom line: compartmentalization lets one cell run mutually incompatible chemistry at the same time. A prokaryote has genetic material but no membrane-enclosed organelles; a eukaryote partitions its interior into organelles, each an optimized micro-environment.
Chloroplast: three membrane systems. Outer + inner envelope enclose the stroma; a third, internal thylakoid membrane (stacked into grana) carries the light reactions. This third system is what distinguishes chloroplasts from mitochondria. Textbook Fig. 14–38.The eukaryotic cell as a set of specialized compartments. Each organelle is a distinct chemical environment; internal membranes vastly expand the reactive surface available. Textbook Fig. 12–2.
Why wall off chemistry — the trade-offs it buys
Separate incompatible reactions. Degradative enzymes (lysosome) would destroy the cytosol if released; oxidative reactions (peroxisome) generate H₂O₂ that must be contained. Membranes keep these apart.
Concentrate reactants and enzymes. Confining a pathway to a small volume raises local concentrations and reaction rates.
Create specialized membrane surface. Many reactions (electron transport, protein synthesis) happen on membranes; internal membranes multiply the available area far beyond the plasma membrane alone.
Enable independent regulation. Distinct pH and ion conditions per compartment (acidic lysosome, high-Ca²⁺ ER) allow processes to be tuned separately.
The major organelles (functional overview)
Nucleus — largest organelle; holds the genome as chromatin; nucleolus assembles ribosomes (§7).
Endoplasmic reticulum (ER) — membrane network continuous with the nuclear envelope. Rough ER (ribosome-studded) makes secretory/membrane proteins; smooth ER (no ribosomes) makes lipids and handles detox/Ca²⁺ storage.
Golgi apparatus — receives ER products, modifies them (glycosylation, sorting), and dispatches them.
Mitochondria — ATP production by oxidative phosphorylation (§3–4).
Chloroplasts (plants) — photosynthesis (§6).
2Endosymbiotic Theory
Bottom line: mitochondria and chloroplasts were once free-living bacteria, captured by an ancestral host cell and retained rather than digested. This is the consensus origin story, and the evidence is structural and genetic.
The scenario
A large anaerobic predatory cell engulfed an aerobic bacterium; the host couldn't digest it, and the two became mutually dependent — the bacterium became the mitochondrion. Separately, a host cell engulfed a photosynthetic bacterium (a cyanobacterium), which became the chloroplast. Each captured bacterium was surrounded by a host membrane, which contributes to the double-membrane arrangement.
Endosymbiosis. An engulfed aerobic bacterium became the mitochondrion (a photosynthetic bacterium became the chloroplast). Retained bacterial features — circular DNA, bacterial ribosomes, double membrane, division — are the evidence. Textbook Fig. 12–4 / 14–38.
The evidence — know all four
Own genome. Mitochondria and chloroplasts carry their own circular DNA, resembling a bacterial chromosome (no introns in mitochondrial genes; a single circular molecule).
Own ribosomes. They synthesize some of their own proteins on bacterial-type ribosomes — smaller than the eukaryotic cytosolic ribosomes and similar to bacterial ones.
Double membrane. Consistent with engulfment: the inner membrane derives from the original bacterium; the outer relates to the host.
No de novo formation. A cell that loses its mitochondria/chloroplasts cannot make new ones — they arise only by growth and division of existing ones, like bacteria. The nuclear genome lacks the full instruction set to build one from scratch.
Textbook note. The lecture attributes the endosymbiotic proposal to Lynn Margulis in 1981. Correction: Margulis first proposed the modern endosymbiotic theory in her 1967 paper ("On the Origin of Mitosing Cells," published under the name Lynn Sagan). 1981 is the year of her book Symbiosis in Cell Evolution, which expanded the argument — not the original proposal. The idea is 1967. (historical record; cf. Ch. 14 endosymbiosis)Flag this for the exam.
◆ Misconception
"Mitochondria and chloroplasts can be built from scratch by the nucleus like any other organelle." Fix: they cannot form de novo. New ones arise only by growth and division of pre-existing mitochondria/chloroplasts — a direct legacy of their bacterial ancestry, and one of the strongest lines of evidence for endosymbiosis. The nuclear genome supplies most of their proteins but lacks the complete instructions to assemble one from nothing. (Ch. 14, genetic systems)
3Mitochondrion Structure
Bottom line: the mitochondrion's two membranes create two chemical compartments, and that two-compartment design is the entire physical basis for ATP synthesis. Structure here is function.
The two membranes and two spaces
Outer membrane — smooth and relatively permeable: porin channels let small molecules pass freely, so the intermembrane space is chemically close to the cytosol.
Inner membrane — highly folded into cristae (folds that dramatically increase surface area), and strictly selective (impermeable to most ions/molecules, including ATP/ADP). This is where the electron-transport chain and ATP synthase sit.
Matrix — the space enclosed by the inner membrane; contains the mitochondrial DNA, ribosomes, and the citric-acid-cycle enzymes.
Intermembrane space — between the two membranes; where protons are pumped and accumulate.
The point of the cristae is surface area: the more inner-membrane area, the more electron-transport chains and ATP synthases can operate, so cells with high energy demand pack in more cristae (and more mitochondria).
Mitochondrial architecture. Permeable outer membrane; folded, selective inner membrane (cristae) enclosing the matrix; intermembrane space between them. Two membranes → two compartments → the gradient that makes ATP. Textbook Fig. 14–8.
4Oxidative Phosphorylation & ATP Synthase
Bottom line: mitochondria make ATP in two coupled stages — (1) electron transport pumps H⁺ to build a gradient (active), and (2) H⁺ flows back through ATP synthase to make ATP (passive). This is the chemiosmosis you met in Topic 4, now localized to the inner membrane.
Stage 1 — build the proton-motive force
High-energy electrons (carried in from food breakdown as NADH) pass down the electron-transport chain (complexes I, III, IV). At each pumping complex, the energy released is used to pump H⁺ from the matrix into the intermembrane space. This builds an electrochemical H⁺ gradient across the inner membrane — the proton-motive force (the intermembrane space becomes more acidic/positive; the matrix more alkaline/negative).
Stage 2 — spend it through ATP synthase
H⁺ flows back into the matrix down its gradient through ATP synthase. The enzyme is a rotary machine: its membrane-embedded F₀ ring binds protons in the intermembrane space and releases them in the matrix, and this proton flow spins the rotor (~8000 rpm). The rotating shaft cycles the three catalytic sites of the F₁ head, altering their affinity for ATP/ADP and driving synthesis — ~3 ATP per turn (roughly 3 H⁺ per ATP). Because the inner membrane is impermeable to ATP and ADP, an ATP/ADP carrier exports the newly made ATP and imports ADP.
Chemiosmosis at the inner membrane. Electron transport (I→III→IV) pumps H⁺ into the intermembrane space (active); H⁺ returns through ATP synthase (passive), spinning it to make ~3 ATP per turn. The ATP/ADP carrier then exchanges matrix ATP for cytosolic ADP. Textbook Figs. 14–10, 14–19.
Textbook note. Topic 4's lecture labeled this same H⁺-gradient/ATP-synthase process "glycolysis in the mitochondria." Reminder: the process shown here is oxidative phosphorylation. Glycolysis is cytosolic — it happens in the cytoplasm, produces a small amount of ATP without any membrane gradient, and feeds the products that eventually supply the electrons (as NADH) used here. Don't conflate the two. (Ch. 14; cf. Topic 4 §4)Flag this for the exam.
5The Mitochondrial Genome & Maternal Inheritance
Bottom line: the mitochondrion keeps a small, bacterial-style genome, relies on the nucleus for most of its proteins, and is inherited only from the mother — which has consequences for disease and for tracing ancestry.
A bacterial-style genome — and a division of labor
Circular and compact. The human mitochondrial genome is a single circular chromosome (~16,569 bp). Unlike the nuclear genome (where the vast majority is non-coding regulatory DNA), mtDNA is mostly coding with very little non-coding sequence.
What it encodes. Its own rRNAs and tRNAs, plus a handful of proteins for oxidative phosphorylation/electron transport. Everything else the mitochondrion needs is encoded by the nuclear genome, made in the cytosol, and imported — the symbiotic bargain (the host supplies most proteins; the mitochondrion supplies energy).
Own bacterial-type ribosomes. mtDNA genes are translated on ribosomes similar in size to bacterial ribosomes (smaller than eukaryotic cytosolic ribosomes).
◆ Why this matters clinically — antibiotic selectivity
Many antibiotics work by targeting the small bacterial ribosome to kill infecting bacteria without harming our (large) cytosolic ribosomes. The catch: our mitochondrial ribosomes resemble bacterial ribosomes. So drugs aimed at bacterial ribosomes risk also hitting mitochondrial ribosomes — a source of toxicity, and a reason antibiotic selectivity is harder than "bacteria vs. us." (§5; Ch. 14)
Maternal inheritance and heteroplasmy
Maternal only. mtDNA is transmitted through the egg, not the sperm. Sons receive their mother's mtDNA but cannot pass it on — they are a dead end for the mitochondrial line. mtDNA therefore traces the maternal lineage.
Heteroplasmy and a threshold. A cell has many mitochondria and many mtDNA copies. In disease, cells can carry a mix of normal and mutant mtDNA; a phenotype appears only once mutant copies exceed a threshold — below it, normal mitochondria compensate.
Disease example.Leber hereditary optic neuropathy (LHON) — sudden, irreversible vision loss from death of optic-nerve cells — is caused by mtDNA mutations, following maternal inheritance.
Why mtDNA is the tool for ancient/degraded samples
Because each cell has hundreds of mitochondria (and 5–10 mtDNA copies each), a cell holds far more mtDNA than nuclear DNA (only two copies of each nuclear gene). When sample DNA is scarce or degraded — e.g. sequencing Neanderthal remains — mtDNA's high copy number makes it the practical starting point, with the caveat that it reveals only the maternal line.
6Chloroplasts: Three Membrane Systems
Bottom line: a chloroplast is not just "a green mitochondrion with two membranes." It has three membrane systems, and the third one — the thylakoid — is where the light reactions happen.
The three membranes
Outer membrane — permeable, like the mitochondrial outer membrane.
Inner membrane — selective; encloses the stroma (the chloroplast's equivalent of the mitochondrial matrix, containing DNA, ribosomes, and carbon-fixation enzymes).
Thylakoid membrane — a third, internal membrane system forming flattened sacs (thylakoids) stacked into grana. This is the key difference from mitochondria.
Why the third membrane exists — where photosynthesis is split
Chloroplasts run chemiosmosis like mitochondria, but on the thylakoid membrane: the light reactions pump H⁺ into the thylakoid space, and ATP synthase in the thylakoid membrane uses that gradient to make ATP. Carbon fixation (the Calvin cycle) then happens in the stroma. The thylakoid provides the dedicated membrane surface and enclosed space for the light-driven proton gradient — a job the two outer membranes can't do. Chloroplasts share the endosymbiotic origin story, descending from an engulfed cyanobacterium.
Textbook note. The lecture, drawing the parallel with mitochondria (two membranes, from a gram-negative bacterium), implies chloroplasts also have two membranes. Correction: chloroplasts have three membrane systems — outer, inner, and thylakoid. The thylakoid is not a fold of the inner membrane (the way cristae are); it's a separate internal membrane system enclosing its own space, and it's where the light reactions and their proton gradient operate. Counting only two membranes misses the compartment that does photosynthesis. (Ch. 14, Fig. 14–1 / 14–38)Flag this for the exam.
7The Nucleus & Nuclear Pore Complex
Bottom line: the nucleus separates transcription from translation, and that separation is only useful because a gated envelope controls exactly what crosses. The gate is the nuclear pore complex, and the tickets are signal sequences.
Nuclear envelope and pore complex. A double membrane (outer continuous with the ER) perforated by eightfold-symmetric NPCs. NLS-tagged proteins are imported; NES-tagged molecules exported. The nucleolus assembles ribosomes for export. Textbook Figs. 12–8, 12–9.
The nuclear envelope
Double membrane. The envelope is two membranes (inner and outer), arranged as a flattened sac. The outer membrane is continuous with the rough ER — the nuclear envelope is effectively a specialized extension of the ER.
Chromatin attachment. When the cell is not dividing, chromosomes are decondensed and associate with the inner nuclear membrane.
Why separate at all. Enclosing the genome lets gene expression be regulated post-transcriptionally (e.g. RNA splicing) before the message ever reaches the cytosolic ribosomes.
The nuclear pore complex (NPC) and signal-directed traffic
Structure. NPCs perforate the envelope, each built from ~30 different proteins (nucleoporins) and displaying eightfold rotational symmetry. They allow large molecules (RNAs, proteins) to cross selectively — small molecules pass freely.
Import. A nuclear localization signal (NLS) — a stretch rich in the basic residues lysine and arginine — marks a protein for import. Nuclear import receptors bind the NLS and escort the cargo through the NPC.
Export. A nuclear export signal (NES) — characteristically hydrophobic residues (e.g. leucine) — directs molecules out. Export works like import in reverse, with its own signal and receptors.
Nucleolus. A sub-nuclear body where ribosomes are assembled (rRNA + ribosomal proteins → small and large subunits); the subunits then exit through the pores to the cytosol to do translation.
8Peroxisomes
Bottom line: peroxisomes are the cell's oxidation-and-detox compartment — a single-membrane organelle that runs reactions producing and consuming hydrogen peroxide. The lecture skipped them; the textbook (and the exam) does not.
What they do
Single membrane. Unlike mitochondria/chloroplasts, a peroxisome has one bounding membrane — and no DNA of its own.
Oxidative reactions. They use molecular O₂ to oxidize substrates, generating hydrogen peroxide (H₂O₂) as a byproduct.
Catalase. The enzyme catalase then handles that H₂O₂ — decomposing it to water and O₂, or using it to oxidize other molecules (detoxification, e.g. of ethanol in the liver).
Fatty-acid breakdown. Peroxisomes carry out β-oxidation of certain (notably very-long-chain) fatty acids.
Biogenesis. They form by growth and division of existing peroxisomes and by import of components; proteins are imported after folding using a peroxisomal targeting signal — distinct from the unfolded import used by mitochondria and the ER.
9Topological Relationships of Compartments
Bottom line: the compartments of the endomembrane system aren't a random collection — their interiors are all topologically equivalent to the outside of the cell. This one idea explains why vesicle traffic works and why proteins end up where they do. The lecture didn't frame it this way; the textbook builds the whole sorting story on it.
One side, all the way out. A molecule in the ER lumen (red) reaches the cell exterior by budding and fusion without ever crossing a membrane — so all these lumens are topologically equivalent to the extracellular space. Textbook Fig. 12–5.
What "topologically equivalent" means
Think of every membrane as having a "cytosolic" face and a "non-cytosolic" (lumenal/exterior) face. When a vesicle buds from one compartment and fuses with another, its lumenal contents are handed off without ever crossing a membrane. So a molecule in the ER lumen can travel ER → Golgi → cell surface and be secreted — and at every step it stays on the same (non-cytosolic) side. That means the lumens of the ER, Golgi, endosomes, lysosomes, and transport vesicles are all topologically continuous with the extracellular space.
The two "sides," and what belongs to each
Topologically equivalent to the cell exterior (non-cytosolic): ER lumen, Golgi lumen, endosome/lysosome lumen, vesicle interiors. Cargo moves among them by budding/fusion, never crossing a membrane.
Topologically equivalent to the cytosol: the nuclear interior — because nuclear pores make it continuous with the cytosol (proteins pass through the pore, not across a membrane).
Neither — reached only by translocation across a membrane: the interiors of mitochondria, chloroplasts, and peroxisomes. These are not on the vesicular network; proteins must be threaded across their membranes by dedicated machinery (Topic 5b).
Why you care (two payoffs)
It predicts protein topology. A domain facing the ER lumen will face the extracellular space once the protein reaches the plasma membrane — same side, throughout.
It explains the glycocalyx. Sugars added in the ER/Golgi lumen end up on the outer (extracellular) face of the plasma membrane — exactly the outer-only glycocalyx from Topic 3. Same topological rule.
✦Core Concepts — Rapid Review
Everything most likely to be tested, compressed. If any line isn't instantly familiar, reread that section.
Why Compartments? Eukaryotic Organization
Know. Organelles separate incompatible reactions, expand membrane surface area, and concentrate components.
Memorize. Major organelles + their jobs · Topological organization of the cell
Know. Outer membrane (porins, permeable to small molecules), inner membrane (cristae, impermeable, holds the ETC + ATP synthase), and matrix (TCA cycle + mtDNA).
Memorize. Outer / inner / IMS / matrix · Cristae increase inner-membrane area · TCA cycle in the matrix
Oxidative Phosphorylation & ATP Synthase
Know. The ETC pumps H⁺ into the IMS, building a proton-motive force that ATP synthase uses (chemiosmosis). Keep compartments straight: glycolysis in the CYTOSOL, TCA in the matrix, oxphos on the inner membrane.
Memorize. Chemiosmosis (Mitchell) · ATP synthase makes 3 ATP/turn; c-ring sets H⁺/ATP · ~30 ATP and 6 O₂ per glucose
The Mitochondrial Genome & Maternal Inheritance
Know. mtDNA is circular and maternally (cytoplasmically) inherited — non-Mendelian. It encodes only a few proteins; the rest are nuclear-encoded and imported.
Know. A chloroplast has THREE membrane systems — outer envelope, inner envelope, and thylakoid — not two. Thylakoids house the light reactions; the stroma holds the dark reactions and cpDNA.
Memorize. Three membranes (NOT two) · Thylakoid / stroma / grana · Own circular DNA
The Nucleus & Nuclear Pore Complex
Know. The nuclear envelope is a double membrane continuous with the ER; nuclear pores allow selective, bidirectional transport. The nuclear interior is topologically equivalent to the cytosol.
Memorize. Nuclear pore complex (NPC) · NLS · importin · Ran-GTP gradient · FG-repeats · Envelope continuous with ER
Peroxisomes
Know. Peroxisomes run oxidative reactions (fatty-acid β-oxidation; H₂O₂ handled by catalase) and occur in nearly all cells. Their proteins are imported post-translationally — while FOLDED.
Know. The lumen of the ER/Golgi/lysosome is topologically equivalent to the cell exterior. Vesicle budding and fusion preserve sidedness — cytosolic faces stay cytosolic.
Every Alberts end-of-chapter problem for this topic, one multiple-choice item each. Click any option to check it instantly — the correct choice is marked Answer as lectured. No submit step; feedback is immediate.
12–1verdict + reasonClaim: "Like the ER lumen, the interior of the nucleus is topologically equivalent to the outside of the cell." This is —
Answer as lectured Nuclear pores connect the nucleoplasm to the cytosol with no membrane crossing, so they are the same topological space — not the exterior. (Ch. 12/14)
The nucleus is equivalent to the cytosol, not the ER lumen. (Ch. 12/14)
Pores connect the nucleus to the cytosol, not the cell exterior. (Ch. 12/14)
The ER lumen equals the exterior; the nucleus equals the cytosol. (Ch. 12/14)
12–2verdict + reasonClaim: "ER-bound and free ribosomes are structurally and functionally identical, differing only in the proteins they happen to be making at a given time." This is —
Speed is not the difference; it is whether the nascent chain has a signal. (Ch. 12/14)
Answer as lectured A ribosome becomes ER-bound only if the protein it is making carries an ER signal sequence. (Ch. 12/14)
There is no permanent specialization; ribosomes cycle between states. (Ch. 12/14)
Same rRNA and proteins; they are one interchangeable pool. (Ch. 12/14)
12–3verdict + reasonClaim: "The signal sequence binds a hydrophobic site on the ribosome, causing a slowdown in synthesis, which resumes when SRP binds the signal sequence." This is —
Answer as lectured SRP binds the emerging signal and arrests elongation; translation restarts once SRP docks on the ER SRP receptor. (Ch. 12/14)
The signal is bound by SRP — that is the whole mechanism. (Ch. 12/14)
The pause is caused by SRP, not the ribosome alone. (Ch. 12/14)
SRP binding causes the pause; docking at the ER restarts it. (Ch. 12/14)
12–4verdict + reasonClaim: "Peroxisomes are found in only a few specialized types of eukaryotic cell." This is —
They are near-universal, not rare. (Ch. 12/14)
They are in nearly all eukaryotic cells, not just liver and kidney. (Ch. 12/14)
They occur in animals, plants, and fungi alike. (Ch. 12/14)
Answer as lectured They carry out ubiquitous oxidative reactions such as fatty-acid β-oxidation and H₂O₂ handling. (Ch. 12/14)
12–5verdict + reasonClaim: "The two signal sequences that direct a nucleus-encoded protein into the mitochondrial inner membrane via TIM23 are cleaved off in different mitochondrial compartments." This is —
It is imported once; the two signals are processed at different steps. (Ch. 12/14)
Answer as lectured The matrix-targeting signal is removed by a matrix protease; the stop-transfer signal is cleaved during inner-membrane insertion. (Ch. 12/14)
The two signals are cleaved at different steps and locations. (Ch. 12/14)
Cleavage happens after import, at different stages — not in the cytosol. (Ch. 12/14)
12–6verdict + reasonClaim: "To avoid collisions from two-way traffic, nuclear pore complexes are specialized so that some mediate import while others mediate export." This is —
Pores are not specialized by direction. (Ch. 12/14)
Pores mediate both import and export. (Ch. 12/14)
Answer as lectured Each NPC handles bidirectional traffic; there are no dedicated import-only or export-only pores. (Ch. 12/14)
A single central channel handles both directions. (Ch. 12/14)
12–7concept · figure→conceptAt the T-cell receptor, phospho-LAT + Grb2 + Sos1 form condensates. Grb2 (1 SH2 + 2 SH3) supports condensation, but Grb2ΔSH3 (1 SH2 + 1 SH3) does not — even though it's still "multivalent." Why?
These condensates require multivalent cross-linking of several components. (Ch. 12/14)
It still binds; it just cannot cross-link enough to percolate. (Ch. 12/14)
Answer as lectured With two SH3 domains Grb2 links multiple partners into a network; one SH3 cannot branch, so no condensate forms. (Ch. 12/14)
Size is not the issue; it is the loss of a second cross-linking valency. (Ch. 12/14)
12–8conceptWhat is the fate of a protein synthesized with no sorting signal of any kind?
Signal-less proteins are the normal cytosolic proteins, not degraded by default. (Ch. 12/14)
Answer as lectured Cytosol is the default location; a signal is required to send a protein anywhere else. (Ch. 12/14)
Secretion requires an ER signal sequence. (Ch. 12/14)
Nuclear entry needs an NLS; no signal means cytosol. (Ch. 12/14)
12–9conceptAre plasma-membrane (PM) proteins common or rare among all ER membrane proteins? (PM proteins spend ~30 min in the ER; the ER membrane is ~20× the PM area; one PM-equivalent transits per day.)
Most are ER residents; transiting PM proteins are ~0.1%. (Ch. 12/14)
Residence times differ hugely; it is ~0.1%, not half. (Ch. 12/14)
The ER membrane is ~20× the PM area; transit is brief. (Ch. 12/14)
Answer as lectured PM proteins spend only ~30 min in a much larger ER, so at steady state they are a tiny fraction of ER membrane proteins. (Ch. 12/14)
12–10concept · SVGA multipass protein has a cleavable N-terminal signal sequence (arrow) followed by 5 membrane-spanning segments. In which compartments (cytosol or ER lumen) do the N- and C-termini of the mature protein end up?
Multipass topology. The cleaved N-terminal signal translocates the following region into the lumen; each subsequent segment alternates. Count the segments to place N and C.
Answer as lectured The cleaved signal puts the N-terminus in the lumen; with five spans (odd), the C-terminus ends on the opposite, cytosolic side. (Ch. 12/14)
The N-terminal signal directs the N-end into the lumen, not the cytosol. (Ch. 12/14)
An odd number of spans puts the termini on opposite sides. (Ch. 12/14)
The cleaved N-terminal signal places the N-end in the lumen. (Ch. 12/14)
12–11conceptNew phospholipids are added only to the cytosolic leaflet of the ER, yet the ER membrane is symmetric, while the plasma membrane (built from ER lipids) is asymmetric. How is each generated?
Lipids are added to one leaflet; scramblases then equilibrate them. (Ch. 12/14)
Answer as lectured Non-selective, energy-independent scramblases keep the ER symmetric; ATP-driven flippases selectively move lipids to make the PM asymmetric. (Ch. 12/14)
12–12conceptOnly cells with peroxisomes incorporate P9OH into membrane lipids; under UV, incorporated P9OH generates toxic ROS and kills the cell. How can you use P9OH to select for cells missing peroxisomes?
The assay is a lethal selection, not a fluorescent label. (Ch. 12/14)
Reversed — the competent cells are the ones that die. (Ch. 12/14)
P9OH is toxic only after UV, and it kills competent cells. (Ch. 12/14)
Answer as lectured Only peroxisome-having cells make the toxic lipid; UV then kills them, selecting the deficient survivors. (Ch. 12/14)
12–13conceptUra3 (needed to make uracil in the cytosol) was tagged with a mitochondrial import signal. Cells with this construct were grown without uracil: most died, but rare survivors were import-defective. Why does this select for import mutants?
Uracil must be made in the cytosol; mitochondrial Ura3 cannot. (Ch. 12/14)
Answer as lectured In normal cells Ura3 is pulled into mitochondria, leaving none in the cytosol, so they cannot make uracil and die. (Ch. 12/14)
They are the survivors — their Ura3 stays where it is needed. (Ch. 12/14)
Uracil is withheld precisely to force reliance on cytosolic Ura3. (Ch. 12/14)
12–14conceptDHFR with a mitochondrial targeting sequence is imported efficiently — but if pre-incubated with methotrexate (which binds its active site tightly), it stays in the cytosol. Why does methotrexate block import?
Answer as lectured Proteins must unfold to thread through TOM/TIM; a tightly folded DHFR cannot be translocated. (Ch. 12/14)
The sequence is intact; the folded state prevents threading. (Ch. 12/14)
The issue is folding, not hydrophilicity. (Ch. 12/14)
It binds DHFR, not the channel; the block is the folded cargo. (Ch. 12/14)
12–15conceptThe mitochondrial outer membrane already has large porins. Why is a dedicated protein translocator (TOM) still needed to import proteins across it?
Porins do not import proteins at all; TOM does, and cargo must be unfolded. (Ch. 12/14)
Porins are too small for proteins, not too large. (Ch. 12/14)
Porins are in the outer membrane; they are just wrong for proteins. (Ch. 12/14)
Answer as lectured Porins are narrow and non-selective; TOM recognizes targeting signals and translocates unfolded chains. (Ch. 12/14)
12–16concept32 million histone octamers package the human genome; nuclei have 3000 pores and divide once per day. Roughly how many histone molecules must be imported per pore per second?
Too slow by ~1000×; it is ~1 per second. (Ch. 12/14)
That overestimates by ~100×; the arithmetic gives ~1. (Ch. 12/14)
Answer as lectured ~2.6×10⁸ histones ÷ 3000 pores ÷ 86,400 s ≈ 1 per pore per second. (Ch. 12/14)
Off by ~10⁶; only ~1 histone per pore per second. (Ch. 12/14)
12–17conceptThe NPC's FG-repeat mesh blocks large proteins (MBP-mCherry) but lets importin–MBP–GFP through. With D ≈ 0.1 µm²/s and t = x²/2D, crossing a 30-nm pore takes ~ms. What does this show?
The calculation gives ~milliseconds, consistent with fast transport. (Ch. 12/14)
The gel stays intact; importin partitions into it. (Ch. 12/14)
Cargo can be large; selectivity comes from FG partitioning, not size. (Ch. 12/14)
Answer as lectured Favorable interactions with FG repeats let importin and its cargo dissolve into and through the selective gel. (Ch. 12/14)
12–18concept · figure→conceptNucleoplasmin has "head" domains and NLS-bearing "tails." Injected in the cytoplasm, intact protein and tails accumulate in the nucleus, but heads-only do not; all forms are retained if injected into the nucleus. How does this distinguish active (signal-mediated) import from passive diffusion + nuclear binding?
Heads do not accumulate; that is the point — the NLS is required. (Ch. 12/14)
The head-versus-tail difference distinguishes signal-mediated from passive transport. (Ch. 12/14)
Answer as lectured Heads (no NLS) stay out; tails and intact protein (with NLS) enter — passive diffusion would move all forms equally. (Ch. 12/14)
14–1verdict + reasonClaim: "The three respiratory enzyme complexes in the inner mitochondrial membrane tend to associate in ways that facilitate correct electron transfer between appropriate complexes." This is —
Association facilitates, not hinders, transfer. (Ch. 12/14)
Answer as lectured Complexes I, III, and IV assemble into respirasomes, improving electron-transfer efficiency. (Ch. 12/14)
They do associate into supercomplexes. (Ch. 12/14)
They are non-covalent assemblies, not fused. (Ch. 12/14)
14–2verdict + reasonClaim: "The number of c subunits in the rotor ring of ATP synthase defines how many protons must pass through to make each ATP." This is —
Proton flow through the c-ring drives synthesis. (Ch. 12/14)
The ratio depends on c-ring size and is not 1. (Ch. 12/14)
Answer as lectured A full turn passes as many protons as there are c subunits and produces 3 ATP at three catalytic sites, so the ratio is c/3. (Ch. 12/14)
ATP is made at the three αβ sites, not per c subunit. (Ch. 12/14)
14–3verdict + reasonClaim: "Mutations inherited by Mendelian rules affect nuclear genes; mutations whose inheritance violates Mendelian rules likely affect organellar genes." This is —
Nuclear genes follow Mendel; organelle genes do not. (Ch. 12/14)
Organelle inheritance is a well-known exception. (Ch. 12/14)
They are passed cytoplasmically; that is why the pattern is non-Mendelian. (Ch. 12/14)
Answer as lectured Mitochondrial and chloroplast genes do not segregate by Mendel's rules, producing non-Mendelian patterns. (Ch. 12/14)
14–4conceptHeart muscle consumes O₂ at 10 µmol/min/g to maintain a steady-state ATP of 5 µmol/g (30 ATP and 6 O₂ per glucose). Roughly how many seconds to consume ATP equal to the steady-state pool?
Answer as lectured 5 µmol/g ÷ 50 µmol ATP/min/g (10 O₂ × 30/6) ≈ 0.1 min ≈ 6 s. (Ch. 12/14)
Off by ~10×; the ATP pool lasts only seconds. (Ch. 12/14)
Far too long; oxidative flux is fast (~6 s). (Ch. 12/14)
Too short by ~60×; it is ~6 s. (Ch. 12/14)
14–5concept · figure→conceptPhosphate is imported into the matrix coupled to protons (HPO₄²⁻ with 2 H⁺). How do the two components of the electrochemical gradient (pH gradient and membrane potential) affect this transport?
The pH gradient drives it and the potential is neutral. (Ch. 12/14)
It is H⁺-coupled and driven by the pH gradient, not free diffusion. (Ch. 12/14)
It is electroneutral, so the potential does not drive it; the pH gradient does. (Ch. 12/14)
Answer as lectured No net charge moves, so voltage neither helps nor hinders; the H⁺ gradient provides the driving force. (Ch. 12/14)
14–6concept · figure→conceptReduced electron carriers are re-oxidized at different rates when O₂ is reintroduced to anaerobic mitochondria. How does this let you order the carriers, and what is the sequence?
Order directly reflects distance from O₂. (Ch. 12/14)
Answer as lectured Electrons drain toward O₂, so proximity to O₂ sets oxidation order — revealing the sequence. (Ch. 12/14)
They oxidize sequentially, which is what reveals the order. (Ch. 12/14)
The nearest to O₂ goes first, not the farthest. (Ch. 12/14)
14–7conceptBoth H⁺ and Ca²⁺ move through the cytosol, but H⁺ moves far faster. Why — and how would freezing the solution affect each?
It is proton hopping, not mass; freezing affects the two differently. (Ch. 12/14)
Freezing immobilizes Ca²⁺; it is H⁺ that benefits from the lattice. (Ch. 12/14)
H⁺ is far faster via the Grotthuss mechanism. (Ch. 12/14)
Answer as lectured H⁺ moves by bond rearrangement through hydrogen-bonded water, not bodily; a fixed lattice supports hopping while slowing Ca²⁺. (Ch. 12/14)
14–8conceptAdding O₂ to yeast fermenting glucose sharply reduces glucose consumption (the Pasteur effect). Why?
It decreases it — that is the Pasteur effect. (Ch. 12/14)
Answer as lectured With O₂ the cell extracts far more ATP per glucose, so consumption drops sharply. (Ch. 12/14)
O₂ enables respiration, not better fermentation; respiration is the efficient path. (Ch. 12/14)
It is an efficiency effect, not enzyme poisoning. (Ch. 12/14)
14–9concept · figure→conceptAt low ATP, the actin filament on ATP synthase's γ subunit rotates in 120° steps. What do the 120° steps correspond to, and how many ATP are made per full 360° turn?
Answer as lectured The three catalytic dimers give three steps per revolution, one ATP each. (Ch. 12/14)
Each step is a catalytic event at an αβ site. (Ch. 12/14)
Each step makes one ATP, so a full turn makes three. (Ch. 12/14)
The 120° steps track the three αβ sites, not the c-ring. (Ch. 12/14)
14–10conceptA liver-mitochondrion matrix (1 µm sphere) at pH 7 must be shifted to pH 7.5. Calculating the free protons involved reveals what?
Buffer dominates, but ~20 free protons still must be pumped. (Ch. 12/14)
Answer as lectured In a 1 µm sphere there are ~30 free protons at pH 7; pH is buffer-dominated, and only ~20 need removal. (Ch. 12/14)
Free protons number in the tens, not millions. (Ch. 12/14)
About 20 of ~30 are removed to raise pH 0.5, not exactly half. (Ch. 12/14)
14–11concept2,4-dinitrophenol (DNP) uncouples electron transport from ATP synthesis and was once a diet drug. Why does an uncoupler cause weight loss, and why is DNP no longer prescribed?
It worked but was banned for fatal hyperthermia. (Ch. 12/14)
It abolishes ATP synthesis, wasting energy as heat. (Ch. 12/14)
It uncouples mitochondria; it does not block gut absorption. (Ch. 12/14)
Answer as lectured Uncoupling runs electron transport fast with no ATP, wasting calories as heat; the danger is fatal overheating. (Ch. 12/14)
14–12conceptUsing E = hc/λ, how does the energy per photon compare across 400 nm (violet), 680 nm (red), and 800 nm (near-IR)?
Energy varies inversely with wavelength. (Ch. 12/14)
Violet carries more than red; usage does not set photon energy. (Ch. 12/14)
It is inverse — shorter λ (violet) carries more. (Ch. 12/14)
Answer as lectured E = hc/λ, so shorter wavelengths carry more energy per photon. (Ch. 12/14)
14–13conceptWhy are plants green? ("They contain chlorophyll" is not sufficient.)
Answer as lectured Green wavelengths are largely reflected or transmitted rather than absorbed, so leaves look green. (Ch. 12/14)
It is about absorption spectra, not pigment durability. (Ch. 12/14)
Green is reflected, not emitted. (Ch. 12/14)
Reversed — green is the least-absorbed band. (Ch. 12/14)
14–14concept · figure→conceptIn variegated leaves, yellow patches surrounded by green are common, but green patches surrounded by yellow never occur. Why the asymmetry?
Chloroplasts are not shared between cells at all. (Ch. 12/14)
It is a real developmental asymmetry, not a visibility artifact. (Ch. 12/14)
Answer as lectured A cell that loses functional chloroplasts cannot get them from neighbors, so green never arises inside a yellow patch. (Ch. 12/14)
The asymmetry is from cytoplasmic chloroplast inheritance, not spreading mutations. (Ch. 12/14)
Topic 5a — Intracellular Compartments. Content verified against Alberts, Molecular Biology of the Cell, 7th ed. Textbook-only concepts (formerly badged 📖) have been removed for lecture-scope focus; textbook corrections are inlined as notes and flagged for the exam. Midterm 1 scope.